Optimal. Leaf size=147 \[ \frac {15 i x}{16 a^4}-\frac {\log (\cos (c+d x))}{a^4 d}+\frac {15}{16 a^4 d (1+i \tan (c+d x))}+\frac {7 \tan ^2(c+d x)}{16 a^4 d (1+i \tan (c+d x))^2}-\frac {\tan ^4(c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {i \tan ^3(c+d x)}{4 a d (a+i a \tan (c+d x))^3} \]
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Rubi [A]
time = 0.24, antiderivative size = 147, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 7, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.292, Rules used = {3639, 3676,
3670, 3556, 12, 3607, 8} \begin {gather*} \frac {7 \tan ^2(c+d x)}{16 a^4 d (1+i \tan (c+d x))^2}+\frac {15}{16 a^4 d (1+i \tan (c+d x))}-\frac {\log (\cos (c+d x))}{a^4 d}+\frac {15 i x}{16 a^4}-\frac {\tan ^4(c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {i \tan ^3(c+d x)}{4 a d (a+i a \tan (c+d x))^3} \end {gather*}
Antiderivative was successfully verified.
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Rule 8
Rule 12
Rule 3556
Rule 3607
Rule 3639
Rule 3670
Rule 3676
Rubi steps
\begin {align*} \int \frac {\tan ^5(c+d x)}{(a+i a \tan (c+d x))^4} \, dx &=-\frac {\tan ^4(c+d x)}{8 d (a+i a \tan (c+d x))^4}-\frac {\int \frac {\tan ^3(c+d x) (-4 a+8 i a \tan (c+d x))}{(a+i a \tan (c+d x))^3} \, dx}{8 a^2}\\ &=-\frac {\tan ^4(c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {i \tan ^3(c+d x)}{4 a d (a+i a \tan (c+d x))^3}+\frac {\int \frac {\tan ^2(c+d x) \left (-36 i a^2-48 a^2 \tan (c+d x)\right )}{(a+i a \tan (c+d x))^2} \, dx}{48 a^4}\\ &=\frac {7 \tan ^2(c+d x)}{16 a^4 d (1+i \tan (c+d x))^2}-\frac {\tan ^4(c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {i \tan ^3(c+d x)}{4 a d (a+i a \tan (c+d x))^3}-\frac {\int \frac {\tan (c+d x) \left (168 a^3-192 i a^3 \tan (c+d x)\right )}{a+i a \tan (c+d x)} \, dx}{192 a^6}\\ &=\frac {7 \tan ^2(c+d x)}{16 a^4 d (1+i \tan (c+d x))^2}-\frac {\tan ^4(c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {i \tan ^3(c+d x)}{4 a d (a+i a \tan (c+d x))^3}+\frac {i \int \frac {360 i a^4 \tan (c+d x)}{a+i a \tan (c+d x)} \, dx}{192 a^7}+\frac {\int \tan (c+d x) \, dx}{a^4}\\ &=-\frac {\log (\cos (c+d x))}{a^4 d}+\frac {7 \tan ^2(c+d x)}{16 a^4 d (1+i \tan (c+d x))^2}-\frac {\tan ^4(c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {i \tan ^3(c+d x)}{4 a d (a+i a \tan (c+d x))^3}-\frac {15 \int \frac {\tan (c+d x)}{a+i a \tan (c+d x)} \, dx}{8 a^3}\\ &=-\frac {\log (\cos (c+d x))}{a^4 d}+\frac {7 \tan ^2(c+d x)}{16 a^4 d (1+i \tan (c+d x))^2}-\frac {\tan ^4(c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {i \tan ^3(c+d x)}{4 a d (a+i a \tan (c+d x))^3}+\frac {15}{16 d \left (a^4+i a^4 \tan (c+d x)\right )}+\frac {(15 i) \int 1 \, dx}{16 a^4}\\ &=\frac {15 i x}{16 a^4}-\frac {\log (\cos (c+d x))}{a^4 d}+\frac {7 \tan ^2(c+d x)}{16 a^4 d (1+i \tan (c+d x))^2}-\frac {\tan ^4(c+d x)}{8 d (a+i a \tan (c+d x))^4}+\frac {i \tan ^3(c+d x)}{4 a d (a+i a \tan (c+d x))^3}+\frac {15}{16 d \left (a^4+i a^4 \tan (c+d x)\right )}\\ \end {align*}
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Mathematica [A]
time = 0.50, size = 126, normalized size = 0.86 \begin {gather*} \frac {\sec ^4(c+d x) (112 \cos (2 (c+d x))+i (32 i+\cos (4 (c+d x)) (i+120 d x+128 i \log (\cos (c+d x)))+96 \sin (2 (c+d x))+\sin (4 (c+d x))+120 i d x \sin (4 (c+d x))-128 \log (\cos (c+d x)) \sin (4 (c+d x))))}{128 a^4 d (-i+\tan (c+d x))^4} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.18, size = 87, normalized size = 0.59
method | result | size |
derivativedivides | \(\frac {\frac {3 i}{4 \left (\tan \left (d x +c \right )-i\right )^{3}}-\frac {49 i}{16 \left (\tan \left (d x +c \right )-i\right )}-\frac {1}{8 \left (\tan \left (d x +c \right )-i\right )^{4}}+\frac {31}{16 \left (\tan \left (d x +c \right )-i\right )^{2}}+\frac {31 \ln \left (\tan \left (d x +c \right )-i\right )}{32}+\frac {\ln \left (\tan \left (d x +c \right )+i\right )}{32}}{d \,a^{4}}\) | \(87\) |
default | \(\frac {\frac {3 i}{4 \left (\tan \left (d x +c \right )-i\right )^{3}}-\frac {49 i}{16 \left (\tan \left (d x +c \right )-i\right )}-\frac {1}{8 \left (\tan \left (d x +c \right )-i\right )^{4}}+\frac {31}{16 \left (\tan \left (d x +c \right )-i\right )^{2}}+\frac {31 \ln \left (\tan \left (d x +c \right )-i\right )}{32}+\frac {\ln \left (\tan \left (d x +c \right )+i\right )}{32}}{d \,a^{4}}\) | \(87\) |
risch | \(\frac {31 i x}{16 a^{4}}+\frac {13 \,{\mathrm e}^{-2 i \left (d x +c \right )}}{16 a^{4} d}-\frac {{\mathrm e}^{-4 i \left (d x +c \right )}}{4 a^{4} d}+\frac {{\mathrm e}^{-6 i \left (d x +c \right )}}{16 a^{4} d}-\frac {{\mathrm e}^{-8 i \left (d x +c \right )}}{128 a^{4} d}+\frac {2 i c}{a^{4} d}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )}{a^{4} d}\) | \(107\) |
norman | \(\frac {\frac {5 \left (\tan ^{6}\left (d x +c \right )\right )}{d a}+\frac {7}{4 d a}+\frac {15 i x}{16 a}+\frac {35 \left (\tan ^{4}\left (d x +c \right )\right )}{4 d a}+\frac {13 \left (\tan ^{2}\left (d x +c \right )\right )}{2 d a}+\frac {15 i x \left (\tan ^{2}\left (d x +c \right )\right )}{4 a}+\frac {45 i x \left (\tan ^{4}\left (d x +c \right )\right )}{8 a}+\frac {15 i x \left (\tan ^{6}\left (d x +c \right )\right )}{4 a}+\frac {15 i x \left (\tan ^{8}\left (d x +c \right )\right )}{16 a}-\frac {15 i \tan \left (d x +c \right )}{16 d a}-\frac {55 i \left (\tan ^{3}\left (d x +c \right )\right )}{16 d a}-\frac {73 i \left (\tan ^{5}\left (d x +c \right )\right )}{16 d a}-\frac {49 i \left (\tan ^{7}\left (d x +c \right )\right )}{16 d a}}{\left (1+\tan ^{2}\left (d x +c \right )\right )^{4} a^{3}}+\frac {\ln \left (1+\tan ^{2}\left (d x +c \right )\right )}{2 a^{4} d}\) | \(227\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: RuntimeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.39, size = 88, normalized size = 0.60 \begin {gather*} \frac {{\left (248 i \, d x e^{\left (8 i \, d x + 8 i \, c\right )} - 128 \, e^{\left (8 i \, d x + 8 i \, c\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} + 1\right ) + 104 \, e^{\left (6 i \, d x + 6 i \, c\right )} - 32 \, e^{\left (4 i \, d x + 4 i \, c\right )} + 8 \, e^{\left (2 i \, d x + 2 i \, c\right )} - 1\right )} e^{\left (-8 i \, d x - 8 i \, c\right )}}{128 \, a^{4} d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 1.83, size = 219, normalized size = 1.49 \begin {gather*} \begin {cases} \frac {\left (106496 a^{12} d^{3} e^{18 i c} e^{- 2 i d x} - 32768 a^{12} d^{3} e^{16 i c} e^{- 4 i d x} + 8192 a^{12} d^{3} e^{14 i c} e^{- 6 i d x} - 1024 a^{12} d^{3} e^{12 i c} e^{- 8 i d x}\right ) e^{- 20 i c}}{131072 a^{16} d^{4}} & \text {for}\: a^{16} d^{4} e^{20 i c} \neq 0 \\x \left (\frac {\left (31 i e^{8 i c} - 26 i e^{6 i c} + 16 i e^{4 i c} - 6 i e^{2 i c} + i\right ) e^{- 8 i c}}{16 a^{4}} - \frac {31 i}{16 a^{4}}\right ) & \text {otherwise} \end {cases} + \frac {31 i x}{16 a^{4}} - \frac {\log {\left (e^{2 i d x} + e^{- 2 i c} \right )}}{a^{4} d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A]
time = 2.08, size = 89, normalized size = 0.61 \begin {gather*} \frac {\frac {12 \, \log \left (\tan \left (d x + c\right ) + i\right )}{a^{4}} + \frac {372 \, \log \left (\tan \left (d x + c\right ) - i\right )}{a^{4}} - \frac {775 \, \tan \left (d x + c\right )^{4} - 1924 i \, \tan \left (d x + c\right )^{3} - 1866 \, \tan \left (d x + c\right )^{2} + 772 i \, \tan \left (d x + c\right ) + 103}{a^{4} {\left (\tan \left (d x + c\right ) - i\right )}^{4}}}{384 \, d} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 3.98, size = 128, normalized size = 0.87 \begin {gather*} \frac {31\,\ln \left (\mathrm {tan}\left (c+d\,x\right )-\mathrm {i}\right )}{32\,a^4\,d}+\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )+1{}\mathrm {i}\right )}{32\,a^4\,d}+\frac {\frac {\mathrm {tan}\left (c+d\,x\right )\,97{}\mathrm {i}}{16\,a^4}+\frac {7}{4\,a^4}-\frac {29\,{\mathrm {tan}\left (c+d\,x\right )}^2}{4\,a^4}-\frac {{\mathrm {tan}\left (c+d\,x\right )}^3\,49{}\mathrm {i}}{16\,a^4}}{d\,\left ({\mathrm {tan}\left (c+d\,x\right )}^4-{\mathrm {tan}\left (c+d\,x\right )}^3\,4{}\mathrm {i}-6\,{\mathrm {tan}\left (c+d\,x\right )}^2+\mathrm {tan}\left (c+d\,x\right )\,4{}\mathrm {i}+1\right )} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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